Bryan and Adam have a total of 600 stickers.
Bryan gives Adam 50 stickers.
Now, Bryan has 70 more than Adam.
- How many stickers does Bryan have at first?
- How many stickers does Adam have in the end?
|
Bryan |
Adam |
Total |
Before |
1 u + 120 |
1 u - 50 |
600 |
Change |
- 50 |
+ 50 |
|
After |
1 u + 70 |
1 u |
2 u + 70 |
(a)
In the end
Number of stickers that Bryan has = 1 u + 70
Number of stickers that Adam has = 1 u
Total number of stickers = 1 u + 1 u + 70 = 2 u + 70
At first
Number of stickers that Bryan has = 1 u + 70 + 50 = 1 u + 120
Number of stickers that Adam has = 1 u - 50
The total number of stickers at first and in the end remains unchanged.
Total number of stickers in the end = Total number of stickers at first
2 u + 70 = 600
2 u = 600 - 70
2 u = 530
1 u = 530 ÷ 2 = 265
Number of stickers that Bryan has at first
= 1 u + 120
= 265 + 120
= 385
(b)
Number of stickers that Adam has in the end
= 1 u
= 265
Answer(s): (a) 385; (b) 265