Adam and Bryan have a total of 600 stickers.
Adam gives Bryan 50 stickers.
Now, Adam has 60 more than Bryan.

1. How many stickers does Adam have at first?
2. How many stickers does Bryan have in the end?

	Adam	Bryan	Total
Before	1 u + 110	1 u - 50	600
Change	- 50	+ 50
After	1 u + 60	1 u	2 u + 60

(a)
In the end
Number of stickers that Adam has = 1 u + 60
Number of stickers that Bryan has = 1 u
Total number of stickers = 1 u + 1 u + 60 = 2 u + 60

At first
Number of stickers that Adam has = 1 u + 60 + 50 = 1 u + 110
Number of stickers that Bryan has = 1 u - 50

The total number of stickers at first and in the end remains unchanged.
Total number of stickers in the end = Total number of stickers at first

2 u + 60 = 600
2 u = 600 - 60
2 u = 540

1 u = 540 ÷ 2 = 270

Number of stickers that Adam has at first
= 1 u + 110
= 270 + 110
= 380

(b)
Number of stickers that Bryan has in the end
= 1 u
= 270

Answer(s): (a) 380; (b) 270