Adam and Bryan have a total of 500 stickers.
Adam gives Bryan 20 stickers.
Now, Adam has 30 more than Bryan.
- How many stickers does Adam have at first?
- How many stickers does Bryan have in the end?
|
Adam |
Bryan |
Total |
Before |
1 u + 50 |
1 u - 20 |
500 |
Change |
- 20 |
+ 20 |
|
After |
1 u + 30 |
1 u |
2 u + 30 |
(a)
In the end
Number of stickers that Adam has = 1 u + 30
Number of stickers that Bryan has = 1 u
Total number of stickers = 1 u + 1 u + 30 = 2 u + 30
At first
Number of stickers that Adam has = 1 u + 30 + 20 = 1 u + 50
Number of stickers that Bryan has = 1 u - 20
The total number of stickers at first and in the end remains unchanged.
Total number of stickers in the end = Total number of stickers at first
2 u + 30 = 500
2 u = 500 - 30
2 u = 470
1 u = 470 ÷ 2 = 235
Number of stickers that Adam has at first
= 1 u + 50
= 235 + 50
= 285
(b)
Number of stickers that Bryan has in the end
= 1 u
= 235
Answer(s): (a) 285; (b) 235