Bryan and Adam have a total of 200 stickers.
Bryan gives Adam 10 stickers.
Now, Bryan has 70 more than Adam.
- How many stickers does Bryan have at first?
- How many stickers does Adam have in the end?
|
Bryan |
Adam |
Total |
Before |
1 u + 80 |
1 u - 10 |
200 |
Change |
- 10 |
+ 10 |
|
After |
1 u + 70 |
1 u |
2 u + 70 |
(a)
In the end
Number of stickers that Bryan has = 1 u + 70
Number of stickers that Adam has = 1 u
Total number of stickers = 1 u + 1 u + 70 = 2 u + 70
At first
Number of stickers that Bryan has = 1 u + 70 + 10 = 1 u + 80
Number of stickers that Adam has = 1 u - 10
The total number of stickers at first and in the end remains unchanged.
Total number of stickers in the end = Total number of stickers at first
2 u + 70 = 200
2 u = 200 - 70
2 u = 130
1 u = 130 ÷ 2 = 65
Number of stickers that Bryan has at first
= 1 u + 80
= 65 + 80
= 145
(b)
Number of stickers that Adam has in the end
= 1 u
= 65
Answer(s): (a) 145; (b) 65