Adam and Bryan have a total of 600 stickers.
Adam gives Bryan 60 stickers.
Now, Adam has 70 more than Bryan.
- How many stickers does Adam have at first?
- How many stickers does Bryan have in the end?
|
Adam |
Bryan |
Total |
Before |
1 u + 130 |
1 u - 60 |
600 |
Change |
- 60 |
+ 60 |
|
After |
1 u + 70 |
1 u |
2 u + 70 |
(a)
In the end
Number of stickers that Adam has = 1 u + 70
Number of stickers that Bryan has = 1 u
Total number of stickers = 1 u + 1 u + 70 = 2 u + 70
At first
Number of stickers that Adam has = 1 u + 70 + 60 = 1 u + 130
Number of stickers that Bryan has = 1 u - 60
The total number of stickers at first and in the end remains unchanged.
Total number of stickers in the end = Total number of stickers at first
2 u + 70 = 600
2 u = 600 - 70
2 u = 530
1 u = 530 ÷ 2 = 265
Number of stickers that Adam has at first
= 1 u + 130
= 265 + 130
= 395
(b)
Number of stickers that Bryan has in the end
= 1 u
= 265
Answer(s): (a) 395; (b) 265