Bryan and Adam have a total of 500 stickers.
Bryan gives Adam 40 stickers.
Now, Bryan has 70 more than Adam.

1. How many stickers does Bryan have at first?
2. How many stickers does Adam have in the end?

	Bryan	Adam	Total
Before	1 u + 110	1 u - 40	500
Change	- 40	+ 40
After	1 u + 70	1 u	2 u + 70

(a)
In the end
Number of stickers that Bryan has = 1 u + 70
Number of stickers that Adam has = 1 u
Total number of stickers = 1 u + 1 u + 70 = 2 u + 70

At first
Number of stickers that Bryan has = 1 u + 70 + 40 = 1 u + 110
Number of stickers that Adam has = 1 u - 40

The total number of stickers at first and in the end remains unchanged.
Total number of stickers in the end = Total number of stickers at first

2 u + 70 = 500
2 u = 500 - 70
2 u = 430

1 u = 430 ÷ 2 = 215

Number of stickers that Bryan has at first
= 1 u + 110
= 215 + 110
= 325

(b)
Number of stickers that Adam has in the end
= 1 u
= 215

Answer(s): (a) 325; (b) 215