Adam, Charlie and Bryan have 48 stickers.
When Adam gives Charlie some stickers, Charlie's stickers is doubled.
When Charlie gives some stickers to Bryan, Bryan's stickers is doubled.
In the end, they have the same number of stickers each.
- How many does each child have in the end?
- How many stickers does Bryan have at first?
- How many stickers does Charlie have at first?
- How many stickers does Adam have at first?
|
Adam |
Charlie |
Bryan |
Before |
28 |
12 |
8 |
Change 1 |
- 12 |
+ 12 |
|
After 1 |
|
24 |
|
Change 2 |
|
- 8 |
+ 8 |
After 2 |
16 |
16 |
16 |
(a)
Number of stickers that each has in the end
= 48 ÷ 3
= 16
(b)
Number of stickers that Bryan has at first
= 16 ÷ 2
= 8
(c)
Number of stickers that Charlie has before giving to Bryan
= 16 + 8
= 24
Number of stickers that Charlie has at first
= 24 ÷ 2
= 12
(d)
Number of stickers that Adam has at first
= 16 + 12
= 28
Answer(s): (a) 16; (b) 8; (c) 12; (d) 28