Charlie, Bryan and Adam have 132 stickers.
When Charlie gives Bryan some stickers, Bryan's stickers is doubled.
When Bryan gives some stickers to Adam, Adam's stickers is doubled.
In the end, they have the same number of stickers each.
- How many does each child have in the end?
- How many stickers does Adam have at first?
- How many stickers does Bryan have at first?
- How many stickers does Charlie have at first?
|
Charlie |
Bryan |
Adam |
Before |
77 |
33 |
22 |
Change 1 |
- 33 |
+ 33 |
|
After 1 |
|
66 |
|
Change 2 |
|
- 22 |
+ 22 |
After 2 |
44 |
44 |
44 |
(a)
Number of stickers that each has in the end
= 132 ÷ 3
= 44
(b)
Number of stickers that Adam has at first
= 44 ÷ 2
= 22
(c)
Number of stickers that Bryan has before giving to Adam
= 44 + 22
= 66
Number of stickers that Bryan has at first
= 66 ÷ 2
= 33
(d)
Number of stickers that Charlie has at first
= 44 + 33
= 77
Answer(s): (a) 44; (b) 22; (c) 33; (d) 77