4 children have the same number of stickers at first.
Christian's number of stickers is tripled.
Adam's number of stickers is quadrupled.
Bryan's number of stickers is doubled.
David's number of stickers is halved.
In the end, they have 380 stickers.

1. How many stickers does Christian have in the end?
2. How many stickers does Adam have in the end?
3. How many stickers does Bryan have in the end?
4. How many stickers does David have in the end?

	Christian	Adam	Bryan	David
Before	1 u	1 u	1 u	1 u
Change	x 3	x 4	x 2	÷ 2
After	3 u	4 u	2 u	0.5 u

(a)
Number of stickers that each child has at first is the same.
Let the number of sticker that each child has at first be 1 u.

Total number of stickers in the end
= 3 u + 4 u + 2 u + 0.5 u
= 9.5 u

9.5 u = 380

1 u = 380 ÷ 9.5 = 40

Number of stickers that Christian has in the end
= 3 u
= 3 x 40
= 120

(b)
Number of stickers that Adam has in the end
= 4 u
= 4 x 40
= 160

(c)
Number of stickers that Bryan has in the end
= 2 u
= 2 x 40
= 80

(d)
Number of stickers that David has in the end
= 0.5 u
= 0.5 x 40
= 20

Answer(s): (a) 120; (b) 160; (c) 80; (d) 20