If Bryan gives 10 stickers to Adam, both will have the same number of stickers.
If Adam gives 8 stickers to Bryan, Bryan has 7 times as many as Adam.
- How many stickers does Bryan have?
- How many stickers does Adam have?
- How many stickers do Bryan and Adam have altogether?
- How many stickers does Bryan have more than Adam?
|
Case 1 |
Case 2 |
|
Bryan |
Adam |
Bryan |
Adam |
Before |
4 u + 10 |
4 u - 10 |
7 u - 8 |
1 u + 8 |
Change |
- 10 |
+ 10 |
+ 8 |
- 8 |
After |
4 u |
4 u |
7 u |
1 u |
(a)
Total number of stickers in the end
= 7 u + 1 u
= 8 u
For scenario 1, Bryan and Adam have same number of stickers in the end.
Number of stickers that each boy has in the end
= 8 u ÷ 2
= 4 u
Number of stickers that Adam has at first in both scenarios is the same.
4 u - 10 = 1 u + 8
4 u - 1 u = 8 + 10
3 u = 18
1 u = 18 ÷ 3 = 6
Number of stickers that Bryan has
= 4 u + 10
= 4 x 6 + 10
= 24 + 10
= 34
(b)
Number of stickers that Adam has
= 1 u + 8
= 6 + 8
= 14
(c)
Total number of stickers
= 34 + 14
= 48
(d)
Number of stickers that Bryan has more than Adam
= 34 - 14
= 20
Answer(s): (a) 34; (b) 14; (c) 48; (d) 20