If Adam gives 7 stickers to Bryan, both will have the same number of stickers.
If Bryan gives 3 stickers to Adam, Adam has 5 times as many as Bryan.
- How many stickers does Adam have?
- How many stickers does Bryan have?
- How many stickers do Adam and Bryan have altogether?
- How many stickers does Adam have more than Bryan?
|
Case 1 |
Case 2 |
|
Adam |
Bryan |
Adam |
Bryan |
Before |
3 u + 7 |
3 u - 7 |
5 u - 3 |
1 u + 3 |
Change |
- 7 |
+ 7 |
+ 3 |
- 3 |
After |
3 u |
3 u |
5 u |
1 u |
(a)
Total number of stickers in the end
= 5 u + 1 u
= 6 u
For scenario 1, Adam and Bryan have same number of stickers in the end.
Number of stickers that each boy has in the end
= 6 u ÷ 2
= 3 u
Number of stickers that Bryan has at first in both scenarios is the same.
3 u - 7 = 1 u + 3
3 u - 1 u = 3 + 7
2 u = 10
1 u = 10 ÷ 2 = 5
Number of stickers that Adam has
= 3 u + 7
= 3 x 5 + 7
= 15 + 7
= 22
(b)
Number of stickers that Bryan has
= 1 u + 3
= 5 + 3
= 8
(c)
Total number of stickers
= 22 + 8
= 30
(d)
Number of stickers that Adam has more than Bryan
= 22 - 8
= 14
Answer(s): (a) 22; (b) 8; (c) 30; (d) 14