If Adam gives 15 stickers to Bryan, both will have the same number of stickers.
If Bryan gives 3 stickers to Adam, Adam has 5 times as many as Bryan.
- How many stickers does Adam have?
- How many stickers does Bryan have?
- How many stickers do Adam and Bryan have altogether?
- How many stickers does Adam have more than Bryan?
|
Case 1 |
Case 2 |
|
Adam |
Bryan |
Adam |
Bryan |
Before |
3 u + 15 |
3 u - 15 |
5 u - 3 |
1 u + 3 |
Change |
- 15 |
+ 15 |
+ 3 |
- 3 |
After |
3 u |
3 u |
5 u |
1 u |
(a)
Total number of stickers in the end
= 5 u + 1 u
= 6 u
For scenario 1, Adam and Bryan have same number of stickers in the end.
Number of stickers that each boy has in the end
= 6 u ÷ 2
= 3 u
Number of stickers that Bryan has at first in both scenarios is the same.
3 u - 15 = 1 u + 3
3 u - 1 u = 3 + 15
2 u = 18
1 u = 18 ÷ 2 = 9
Number of stickers that Adam has
= 3 u + 15
= 3 x 9 + 15
= 27 + 15
= 42
(b)
Number of stickers that Bryan has
= 1 u + 3
= 9 + 3
= 12
(c)
Total number of stickers
= 42 + 12
= 54
(d)
Number of stickers that Adam has more than Bryan
= 42 - 12
= 30
Answer(s): (a) 42; (b) 12; (c) 54; (d) 30