If Adam gives 7 stickers to Bryan, both will have the same number of stickers.
If Bryan gives 13 stickers to Adam, Adam has 11 times as many as Bryan.
- How many stickers does Adam have?
- How many stickers does Bryan have?
- How many stickers do Adam and Bryan have altogether?
- How many stickers does Adam have more than Bryan?
|
Case 1 |
Case 2 |
|
Adam |
Bryan |
Adam |
Bryan |
Before |
6 u + 7 |
6 u - 7 |
11 u - 13 |
1 u + 13 |
Change |
- 7 |
+ 7 |
+ 13 |
- 13 |
After |
6 u |
6 u |
11 u |
1 u |
(a)
Total number of stickers in the end
= 11 u + 1 u
= 12 u
For scenario 1, Adam and Bryan have same number of stickers in the end.
Number of stickers that each boy has in the end
= 12 u ÷ 2
= 6 u
Number of stickers that Bryan has at first in both scenarios is the same.
6 u - 7 = 1 u + 13
6 u - 1 u = 13 + 7
5 u = 20
1 u = 20 ÷ 5 = 4
Number of stickers that Adam has
= 6 u + 7
= 6 x 4 + 7
= 24 + 7
= 31
(b)
Number of stickers that Bryan has
= 1 u + 13
= 4 + 13
= 17
(c)
Total number of stickers
= 31 + 17
= 48
(d)
Number of stickers that Adam has more than Bryan
= 31 - 17
= 14
Answer(s): (a) 31; (b) 17; (c) 48; (d) 14