If Adam gives 2 stickers to Bryan, both will have the same number of stickers.
If Bryan gives 18 stickers to Adam, Adam has 9 times as many as Bryan.
- How many stickers does Adam have?
- How many stickers does Bryan have?
- How many stickers do Adam and Bryan have altogether?
- How many stickers does Adam have more than Bryan?
|
Case 1 |
Case 2 |
|
Adam |
Bryan |
Adam |
Bryan |
Before |
5 u + 2 |
5 u - 2 |
9 u - 18 |
1 u + 18 |
Change |
- 2 |
+ 2 |
+ 18 |
- 18 |
After |
5 u |
5 u |
9 u |
1 u |
(a)
Total number of stickers in the end
= 9 u + 1 u
= 10 u
For scenario 1, Adam and Bryan have same number of stickers in the end.
Number of stickers that each boy has in the end
= 10 u ÷ 2
= 5 u
Number of stickers that Bryan has at first in both scenarios is the same.
5 u - 2 = 1 u + 18
5 u - 1 u = 18 + 2
4 u = 20
1 u = 20 ÷ 4 = 5
Number of stickers that Adam has
= 5 u + 2
= 5 x 5 + 2
= 25 + 2
= 27
(b)
Number of stickers that Bryan has
= 1 u + 18
= 5 + 18
= 23
(c)
Total number of stickers
= 27 + 23
= 50
(d)
Number of stickers that Adam has more than Bryan
= 27 - 23
= 4
Answer(s): (a) 27; (b) 23; (c) 50; (d) 4