If Adam gives 10 stickers to Bryan, both will have the same number of stickers.
If Bryan gives 15 stickers to Adam, Adam has 11 times as many as Bryan.
- How many stickers does Adam have?
- How many stickers does Bryan have?
- How many stickers do Adam and Bryan have altogether?
- How many stickers does Adam have more than Bryan?
|
Case 1 |
Case 2 |
|
Adam |
Bryan |
Adam |
Bryan |
Before |
6 u + 10 |
6 u - 10 |
11 u - 15 |
1 u + 15 |
Change |
- 10 |
+ 10 |
+ 15 |
- 15 |
After |
6 u |
6 u |
11 u |
1 u |
(a)
Total number of stickers in the end
= 11 u + 1 u
= 12 u
For scenario 1, Adam and Bryan have same number of stickers in the end.
Number of stickers that each boy has in the end
= 12 u ÷ 2
= 6 u
Number of stickers that Bryan has at first in both scenarios is the same.
6 u - 10 = 1 u + 15
6 u - 1 u = 15 + 10
5 u = 25
1 u = 25 ÷ 5 = 5
Number of stickers that Adam has
= 6 u + 10
= 6 x 5 + 10
= 30 + 10
= 40
(b)
Number of stickers that Bryan has
= 1 u + 15
= 5 + 15
= 20
(c)
Total number of stickers
= 40 + 20
= 60
(d)
Number of stickers that Adam has more than Bryan
= 40 - 20
= 20
Answer(s): (a) 40; (b) 20; (c) 60; (d) 20