If Adam gives 7 stickers to Bryan, both will have the same number of stickers.
If Bryan gives 9 stickers to Adam, Adam has 9 times as many as Bryan.
- How many stickers does Adam have?
- How many stickers does Bryan have?
- How many stickers do Adam and Bryan have altogether?
- How many stickers does Adam have more than Bryan?
|
Case 1 |
Case 2 |
|
Adam |
Bryan |
Adam |
Bryan |
Before |
5 u + 7 |
5 u - 7 |
9 u - 9 |
1 u + 9 |
Change |
- 7 |
+ 7 |
+ 9 |
- 9 |
After |
5 u |
5 u |
9 u |
1 u |
(a)
Total number of stickers in the end
= 9 u + 1 u
= 10 u
For scenario 1, Adam and Bryan have same number of stickers in the end.
Number of stickers that each boy has in the end
= 10 u ÷ 2
= 5 u
Number of stickers that Bryan has at first in both scenarios is the same.
5 u - 7 = 1 u + 9
5 u - 1 u = 9 + 7
4 u = 16
1 u = 16 ÷ 4 = 4
Number of stickers that Adam has
= 5 u + 7
= 5 x 4 + 7
= 20 + 7
= 27
(b)
Number of stickers that Bryan has
= 1 u + 9
= 4 + 9
= 13
(c)
Total number of stickers
= 27 + 13
= 40
(d)
Number of stickers that Adam has more than Bryan
= 27 - 13
= 14
Answer(s): (a) 27; (b) 13; (c) 40; (d) 14