If Bryan gives 2 stickers to Adam, both will have the same number of stickers.
If Adam gives 2 stickers to Bryan, Bryan has 5 times as many as Adam.
- How many stickers does Bryan have?
- How many stickers does Adam have?
- How many stickers do Bryan and Adam have altogether?
- How many stickers does Bryan have more than Adam?
|
Case 1 |
Case 2 |
|
Bryan |
Adam |
Bryan |
Adam |
Before |
3 u + 2 |
3 u - 2 |
5 u - 2 |
1 u + 2 |
Change |
- 2 |
+ 2 |
+ 2 |
- 2 |
After |
3 u |
3 u |
5 u |
1 u |
(a)
Total number of stickers in the end
= 5 u + 1 u
= 6 u
For scenario 1, Bryan and Adam have same number of stickers in the end.
Number of stickers that each boy has in the end
= 6 u ÷ 2
= 3 u
Number of stickers that Adam has at first in both scenarios is the same.
3 u - 2 = 1 u + 2
3 u - 1 u = 2 + 2
2 u = 4
1 u = 4 ÷ 2 = 2
Number of stickers that Bryan has
= 3 u + 2
= 3 x 2 + 2
= 6 + 2
= 8
(b)
Number of stickers that Adam has
= 1 u + 2
= 2 + 2
= 4
(c)
Total number of stickers
= 8 + 4
= 12
(d)
Number of stickers that Bryan has more than Adam
= 8 - 4
= 4
Answer(s): (a) 8; (b) 4; (c) 12; (d) 4