If Bryan gives 7 stickers to Adam, both will have the same number of stickers.
If Adam gives 18 stickers to Bryan, Bryan has 11 times as many as Adam.
- How many stickers does Bryan have?
- How many stickers does Adam have?
- How many stickers do Bryan and Adam have altogether?
- How many stickers does Bryan have more than Adam?
|
Case 1 |
Case 2 |
|
Bryan |
Adam |
Bryan |
Adam |
Before |
6 u + 7 |
6 u - 7 |
11 u - 18 |
1 u + 18 |
Change |
- 7 |
+ 7 |
+ 18 |
- 18 |
After |
6 u |
6 u |
11 u |
1 u |
(a)
Total number of stickers in the end
= 11 u + 1 u
= 12 u
For scenario 1, Bryan and Adam have same number of stickers in the end.
Number of stickers that each boy has in the end
= 12 u ÷ 2
= 6 u
Number of stickers that Adam has at first in both scenarios is the same.
6 u - 7 = 1 u + 18
6 u - 1 u = 18 + 7
5 u = 25
1 u = 25 ÷ 5 = 5
Number of stickers that Bryan has
= 6 u + 7
= 6 x 5 + 7
= 30 + 7
= 37
(b)
Number of stickers that Adam has
= 1 u + 18
= 5 + 18
= 23
(c)
Total number of stickers
= 37 + 23
= 60
(d)
Number of stickers that Bryan has more than Adam
= 37 - 23
= 14
Answer(s): (a) 37; (b) 23; (c) 60; (d) 14