If Adam gives 7 stickers to Bryan, both will have the same number of stickers.
If Bryan gives 11 stickers to Adam, Adam has 7 times as many as Bryan.
- How many stickers does Adam have?
- How many stickers does Bryan have?
- How many stickers do Adam and Bryan have altogether?
- How many stickers does Adam have more than Bryan?
|
Case 1 |
Case 2 |
|
Adam |
Bryan |
Adam |
Bryan |
Before |
4 u + 7 |
4 u - 7 |
7 u - 11 |
1 u + 11 |
Change |
- 7 |
+ 7 |
+ 11 |
- 11 |
After |
4 u |
4 u |
7 u |
1 u |
(a)
Total number of stickers in the end
= 7 u + 1 u
= 8 u
For scenario 1, Adam and Bryan have same number of stickers in the end.
Number of stickers that each boy has in the end
= 8 u ÷ 2
= 4 u
Number of stickers that Bryan has at first in both scenarios is the same.
4 u - 7 = 1 u + 11
4 u - 1 u = 11 + 7
3 u = 18
1 u = 18 ÷ 3 = 6
Number of stickers that Adam has
= 4 u + 7
= 4 x 6 + 7
= 24 + 7
= 31
(b)
Number of stickers that Bryan has
= 1 u + 11
= 6 + 11
= 17
(c)
Total number of stickers
= 31 + 17
= 48
(d)
Number of stickers that Adam has more than Bryan
= 31 - 17
= 14
Answer(s): (a) 31; (b) 17; (c) 48; (d) 14