If Bryan gives 10 stickers to Adam, both will have the same number of stickers.
If Adam gives 8 stickers to Bryan, Bryan has 5 times as many as Adam.
- How many stickers does Bryan have?
- How many stickers does Adam have?
- How many stickers do Bryan and Adam have altogether?
- How many stickers does Bryan have more than Adam?
|
Case 1 |
Case 2 |
|
Bryan |
Adam |
Bryan |
Adam |
Before |
3 u + 10 |
3 u - 10 |
5 u - 8 |
1 u + 8 |
Change |
- 10 |
+ 10 |
+ 8 |
- 8 |
After |
3 u |
3 u |
5 u |
1 u |
(a)
Total number of stickers in the end
= 5 u + 1 u
= 6 u
For scenario 1, Bryan and Adam have same number of stickers in the end.
Number of stickers that each boy has in the end
= 6 u ÷ 2
= 3 u
Number of stickers that Adam has at first in both scenarios is the same.
3 u - 10 = 1 u + 8
3 u - 1 u = 8 + 10
2 u = 18
1 u = 18 ÷ 2 = 9
Number of stickers that Bryan has
= 3 u + 10
= 3 x 9 + 10
= 27 + 10
= 37
(b)
Number of stickers that Adam has
= 1 u + 8
= 9 + 8
= 17
(c)
Total number of stickers
= 37 + 17
= 54
(d)
Number of stickers that Bryan has more than Adam
= 37 - 17
= 20
Answer(s): (a) 37; (b) 17; (c) 54; (d) 20