If Bryan gives 5 stickers to Adam, both will have the same number of stickers.
If Adam gives 10 stickers to Bryan, Bryan has 7 times as many as Adam.
- How many stickers does Bryan have?
- How many stickers does Adam have?
- How many stickers do Bryan and Adam have altogether?
- How many stickers does Bryan have more than Adam?
|
Case 1 |
Case 2 |
|
Bryan |
Adam |
Bryan |
Adam |
Before |
4 u + 5 |
4 u - 5 |
7 u - 10 |
1 u + 10 |
Change |
- 5 |
+ 5 |
+ 10 |
- 10 |
After |
4 u |
4 u |
7 u |
1 u |
(a)
Total number of stickers in the end
= 7 u + 1 u
= 8 u
For scenario 1, Bryan and Adam have same number of stickers in the end.
Number of stickers that each boy has in the end
= 8 u ÷ 2
= 4 u
Number of stickers that Adam has at first in both scenarios is the same.
4 u - 5 = 1 u + 10
4 u - 1 u = 10 + 5
3 u = 15
1 u = 15 ÷ 3 = 5
Number of stickers that Bryan has
= 4 u + 5
= 4 x 5 + 5
= 20 + 5
= 25
(b)
Number of stickers that Adam has
= 1 u + 10
= 5 + 10
= 15
(c)
Total number of stickers
= 25 + 15
= 40
(d)
Number of stickers that Bryan has more than Adam
= 25 - 15
= 10
Answer(s): (a) 25; (b) 15; (c) 40; (d) 10