If Bryan gives 16 stickers to Adam, both will have the same number of stickers.
If Adam gives 11 stickers to Bryan, Bryan has 7 times as many as Adam.

1. How many stickers does Bryan have?
2. How many stickers does Adam have?
3. How many stickers do Bryan and Adam have altogether?
4. How many stickers does Bryan have more than Adam?

	Case 1		Case 2
	Bryan	Adam	Bryan	Adam
Before	4 u + 16	4 u - 16	7 u - 11	1 u + 11
Change	- 16	+ 16	+ 11	- 11
After	4 u	4 u	7 u	1 u

(a)
Total number of stickers in the end
= 7 u + 1 u
= 8 u

For scenario 1, Bryan and Adam have same number of stickers in the end.

Number of stickers that each boy has in the end
= 8 u ÷ 2
= 4 u

Number of stickers that Adam has at first in both scenarios is the same.

4 u - 16 = 1 u + 11
4 u - 1 u = 11 + 16
3 u = 27

1 u = 27 ÷ 3 = 9

Number of stickers that Bryan has
= 4 u + 16
= 4 x 9 + 16
= 36 + 16
= 52

(b)
Number of stickers that Adam has
= 1 u + 11
= 9 + 11
= 20

(c)
Total number of stickers
= 52 + 20
= 72

(d)
Number of stickers that Bryan has more than Adam
= 52 - 20
= 32

Answer(s): (a) 52; (b) 20; (c) 72; (d) 32