If Bryan gives 2 stickers to Adam, both will have the same number of stickers.
If Adam gives 20 stickers to Bryan, Bryan has 5 times as many as Adam.
- How many stickers does Bryan have?
- How many stickers does Adam have?
- How many stickers do Bryan and Adam have altogether?
- How many stickers does Bryan have more than Adam?
|
Case 1 |
Case 2 |
|
Bryan |
Adam |
Bryan |
Adam |
Before |
3 u + 2 |
3 u - 2 |
5 u - 20 |
1 u + 20 |
Change |
- 2 |
+ 2 |
+ 20 |
- 20 |
After |
3 u |
3 u |
5 u |
1 u |
(a)
Total number of stickers in the end
= 5 u + 1 u
= 6 u
For scenario 1, Bryan and Adam have same number of stickers in the end.
Number of stickers that each boy has in the end
= 6 u ÷ 2
= 3 u
Number of stickers that Adam has at first in both scenarios is the same.
3 u - 2 = 1 u + 20
3 u - 1 u = 20 + 2
2 u = 22
1 u = 22 ÷ 2 = 11
Number of stickers that Bryan has
= 3 u + 2
= 3 x 11 + 2
= 33 + 2
= 35
(b)
Number of stickers that Adam has
= 1 u + 20
= 11 + 20
= 31
(c)
Total number of stickers
= 35 + 31
= 66
(d)
Number of stickers that Bryan has more than Adam
= 35 - 31
= 4
Answer(s): (a) 35; (b) 31; (c) 66; (d) 4