If Adam gives 10 stickers to Bryan, both will have the same number of stickers.
If Bryan gives 20 stickers to Adam, Adam has 7 times as many as Bryan.
- How many stickers does Adam have?
- How many stickers does Bryan have?
- How many stickers do Adam and Bryan have altogether?
- How many stickers does Adam have more than Bryan?
|
Case 1 |
Case 2 |
|
Adam |
Bryan |
Adam |
Bryan |
Before |
4 u + 10 |
4 u - 10 |
7 u - 20 |
1 u + 20 |
Change |
- 10 |
+ 10 |
+ 20 |
- 20 |
After |
4 u |
4 u |
7 u |
1 u |
(a)
Total number of stickers in the end
= 7 u + 1 u
= 8 u
For scenario 1, Adam and Bryan have same number of stickers in the end.
Number of stickers that each boy has in the end
= 8 u ÷ 2
= 4 u
Number of stickers that Bryan has at first in both scenarios is the same.
4 u - 10 = 1 u + 20
4 u - 1 u = 20 + 10
3 u = 30
1 u = 30 ÷ 3 = 10
Number of stickers that Adam has
= 4 u + 10
= 4 x 10 + 10
= 40 + 10
= 50
(b)
Number of stickers that Bryan has
= 1 u + 20
= 10 + 20
= 30
(c)
Total number of stickers
= 50 + 30
= 80
(d)
Number of stickers that Adam has more than Bryan
= 50 - 30
= 20
Answer(s): (a) 50; (b) 30; (c) 80; (d) 20