If Bryan gives 14 stickers to Adam, both will have the same number of stickers.
If Adam gives 7 stickers to Bryan, Bryan has 7 times as many as Adam.
- How many stickers does Bryan have?
- How many stickers does Adam have?
- How many stickers do Bryan and Adam have altogether?
- How many stickers does Bryan have more than Adam?
|
Case 1 |
Case 2 |
|
Bryan |
Adam |
Bryan |
Adam |
Before |
4 u + 14 |
4 u - 14 |
7 u - 7 |
1 u + 7 |
Change |
- 14 |
+ 14 |
+ 7 |
- 7 |
After |
4 u |
4 u |
7 u |
1 u |
(a)
Total number of stickers in the end
= 7 u + 1 u
= 8 u
For scenario 1, Bryan and Adam have same number of stickers in the end.
Number of stickers that each boy has in the end
= 8 u ÷ 2
= 4 u
Number of stickers that Adam has at first in both scenarios is the same.
4 u - 14 = 1 u + 7
4 u - 1 u = 7 + 14
3 u = 21
1 u = 21 ÷ 3 = 7
Number of stickers that Bryan has
= 4 u + 14
= 4 x 7 + 14
= 28 + 14
= 42
(b)
Number of stickers that Adam has
= 1 u + 7
= 7 + 7
= 14
(c)
Total number of stickers
= 42 + 14
= 56
(d)
Number of stickers that Bryan has more than Adam
= 42 - 14
= 28
Answer(s): (a) 42; (b) 14; (c) 56; (d) 28