If Bryan gives 11 stickers to Adam, both will have the same number of stickers.
If Adam gives 15 stickers to Bryan, Bryan has 5 times as many as Adam.
- How many stickers does Bryan have?
- How many stickers does Adam have?
- How many stickers do Bryan and Adam have altogether?
- How many stickers does Bryan have more than Adam?
|
Case 1 |
Case 2 |
|
Bryan |
Adam |
Bryan |
Adam |
Before |
3 u + 11 |
3 u - 11 |
5 u - 15 |
1 u + 15 |
Change |
- 11 |
+ 11 |
+ 15 |
- 15 |
After |
3 u |
3 u |
5 u |
1 u |
(a)
Total number of stickers in the end
= 5 u + 1 u
= 6 u
For scenario 1, Bryan and Adam have same number of stickers in the end.
Number of stickers that each boy has in the end
= 6 u ÷ 2
= 3 u
Number of stickers that Adam has at first in both scenarios is the same.
3 u - 11 = 1 u + 15
3 u - 1 u = 15 + 11
2 u = 26
1 u = 26 ÷ 2 = 13
Number of stickers that Bryan has
= 3 u + 11
= 3 x 13 + 11
= 39 + 11
= 50
(b)
Number of stickers that Adam has
= 1 u + 15
= 13 + 15
= 28
(c)
Total number of stickers
= 50 + 28
= 78
(d)
Number of stickers that Bryan has more than Adam
= 50 - 28
= 22
Answer(s): (a) 50; (b) 28; (c) 78; (d) 22