If Adam gives 8 stickers to Bryan, both will have the same number of stickers.
If Bryan gives 17 stickers to Adam, Adam has 11 times as many as Bryan.
- How many stickers does Adam have?
- How many stickers does Bryan have?
- How many stickers do Adam and Bryan have altogether?
- How many stickers does Adam have more than Bryan?
|
Case 1 |
Case 2 |
|
Adam |
Bryan |
Adam |
Bryan |
Before |
6 u + 8 |
6 u - 8 |
11 u - 17 |
1 u + 17 |
Change |
- 8 |
+ 8 |
+ 17 |
- 17 |
After |
6 u |
6 u |
11 u |
1 u |
(a)
Total number of stickers in the end
= 11 u + 1 u
= 12 u
For scenario 1, Adam and Bryan have same number of stickers in the end.
Number of stickers that each boy has in the end
= 12 u ÷ 2
= 6 u
Number of stickers that Bryan has at first in both scenarios is the same.
6 u - 8 = 1 u + 17
6 u - 1 u = 17 + 8
5 u = 25
1 u = 25 ÷ 5 = 5
Number of stickers that Adam has
= 6 u + 8
= 6 x 5 + 8
= 30 + 8
= 38
(b)
Number of stickers that Bryan has
= 1 u + 17
= 5 + 17
= 22
(c)
Total number of stickers
= 38 + 22
= 60
(d)
Number of stickers that Adam has more than Bryan
= 38 - 22
= 16
Answer(s): (a) 38; (b) 22; (c) 60; (d) 16