If Adam gives 8 stickers to Bryan, both will have the same number of stickers.
If Bryan gives 13 stickers to Adam, Adam has 7 times as many as Bryan.
- How many stickers does Adam have?
- How many stickers does Bryan have?
- How many stickers do Adam and Bryan have altogether?
- How many stickers does Adam have more than Bryan?
|
Case 1 |
Case 2 |
|
Adam |
Bryan |
Adam |
Bryan |
Before |
4 u + 8 |
4 u - 8 |
7 u - 13 |
1 u + 13 |
Change |
- 8 |
+ 8 |
+ 13 |
- 13 |
After |
4 u |
4 u |
7 u |
1 u |
(a)
Total number of stickers in the end
= 7 u + 1 u
= 8 u
For scenario 1, Adam and Bryan have same number of stickers in the end.
Number of stickers that each boy has in the end
= 8 u ÷ 2
= 4 u
Number of stickers that Bryan has at first in both scenarios is the same.
4 u - 8 = 1 u + 13
4 u - 1 u = 13 + 8
3 u = 21
1 u = 21 ÷ 3 = 7
Number of stickers that Adam has
= 4 u + 8
= 4 x 7 + 8
= 28 + 8
= 36
(b)
Number of stickers that Bryan has
= 1 u + 13
= 7 + 13
= 20
(c)
Total number of stickers
= 36 + 20
= 56
(d)
Number of stickers that Adam has more than Bryan
= 36 - 20
= 16
Answer(s): (a) 36; (b) 20; (c) 56; (d) 16