If Adam gives 8 stickers to Bryan, both will have the same number of stickers.
If Bryan gives 10 stickers to Adam, Adam has 5 times as many as Bryan.
- How many stickers does Adam have?
- How many stickers does Bryan have?
- How many stickers do Adam and Bryan have altogether?
- How many stickers does Adam have more than Bryan?
|
Case 1 |
Case 2 |
|
Adam |
Bryan |
Adam |
Bryan |
Before |
3 u + 8 |
3 u - 8 |
5 u - 10 |
1 u + 10 |
Change |
- 8 |
+ 8 |
+ 10 |
- 10 |
After |
3 u |
3 u |
5 u |
1 u |
(a)
Total number of stickers in the end
= 5 u + 1 u
= 6 u
For scenario 1, Adam and Bryan have same number of stickers in the end.
Number of stickers that each boy has in the end
= 6 u ÷ 2
= 3 u
Number of stickers that Bryan has at first in both scenarios is the same.
3 u - 8 = 1 u + 10
3 u - 1 u = 10 + 8
2 u = 18
1 u = 18 ÷ 2 = 9
Number of stickers that Adam has
= 3 u + 8
= 3 x 9 + 8
= 27 + 8
= 35
(b)
Number of stickers that Bryan has
= 1 u + 10
= 9 + 10
= 19
(c)
Total number of stickers
= 35 + 19
= 54
(d)
Number of stickers that Adam has more than Bryan
= 35 - 19
= 16
Answer(s): (a) 35; (b) 19; (c) 54; (d) 16