If Bryan gives 3 stickers to Adam, both will have the same number of stickers.
If Adam gives 12 stickers to Bryan, Bryan has 11 times as many as Adam.
- How many stickers does Bryan have?
- How many stickers does Adam have?
- How many stickers do Bryan and Adam have altogether?
- How many stickers does Bryan have more than Adam?
|
Case 1 |
Case 2 |
|
Bryan |
Adam |
Bryan |
Adam |
Before |
6 u + 3 |
6 u - 3 |
11 u - 12 |
1 u + 12 |
Change |
- 3 |
+ 3 |
+ 12 |
- 12 |
After |
6 u |
6 u |
11 u |
1 u |
(a)
Total number of stickers in the end
= 11 u + 1 u
= 12 u
For scenario 1, Bryan and Adam have same number of stickers in the end.
Number of stickers that each boy has in the end
= 12 u ÷ 2
= 6 u
Number of stickers that Adam has at first in both scenarios is the same.
6 u - 3 = 1 u + 12
6 u - 1 u = 12 + 3
5 u = 15
1 u = 15 ÷ 5 = 3
Number of stickers that Bryan has
= 6 u + 3
= 6 x 3 + 3
= 18 + 3
= 21
(b)
Number of stickers that Adam has
= 1 u + 12
= 3 + 12
= 15
(c)
Total number of stickers
= 21 + 15
= 36
(d)
Number of stickers that Bryan has more than Adam
= 21 - 15
= 6
Answer(s): (a) 21; (b) 15; (c) 36; (d) 6