If Adam gives 2 stickers to Bryan, both will have the same number of stickers.
If Bryan gives 6 stickers to Adam, Adam has 5 times as many as Bryan.
- How many stickers does Adam have?
- How many stickers does Bryan have?
- How many stickers do Adam and Bryan have altogether?
- How many stickers does Adam have more than Bryan?
|
Case 1 |
Case 2 |
|
Adam |
Bryan |
Adam |
Bryan |
Before |
3 u + 2 |
3 u - 2 |
5 u - 6 |
1 u + 6 |
Change |
- 2 |
+ 2 |
+ 6 |
- 6 |
After |
3 u |
3 u |
5 u |
1 u |
(a)
Total number of stickers in the end
= 5 u + 1 u
= 6 u
For scenario 1, Adam and Bryan have same number of stickers in the end.
Number of stickers that each boy has in the end
= 6 u ÷ 2
= 3 u
Number of stickers that Bryan has at first in both scenarios is the same.
3 u - 2 = 1 u + 6
3 u - 1 u = 6 + 2
2 u = 8
1 u = 8 ÷ 2 = 4
Number of stickers that Adam has
= 3 u + 2
= 3 x 4 + 2
= 12 + 2
= 14
(b)
Number of stickers that Bryan has
= 1 u + 6
= 4 + 6
= 10
(c)
Total number of stickers
= 14 + 10
= 24
(d)
Number of stickers that Adam has more than Bryan
= 14 - 10
= 4
Answer(s): (a) 14; (b) 10; (c) 24; (d) 4