If Bryan gives 11 stickers to Adam, both will have the same number of stickers.
If Adam gives 5 stickers to Bryan, Bryan has 9 times as many as Adam.
- How many stickers does Bryan have?
- How many stickers does Adam have?
- How many stickers do Bryan and Adam have altogether?
- How many stickers does Bryan have more than Adam?
|
Case 1 |
Case 2 |
|
Bryan |
Adam |
Bryan |
Adam |
Before |
5 u + 11 |
5 u - 11 |
9 u - 5 |
1 u + 5 |
Change |
- 11 |
+ 11 |
+ 5 |
- 5 |
After |
5 u |
5 u |
9 u |
1 u |
(a)
Total number of stickers in the end
= 9 u + 1 u
= 10 u
For scenario 1, Bryan and Adam have same number of stickers in the end.
Number of stickers that each boy has in the end
= 10 u ÷ 2
= 5 u
Number of stickers that Adam has at first in both scenarios is the same.
5 u - 11 = 1 u + 5
5 u - 1 u = 5 + 11
4 u = 16
1 u = 16 ÷ 4 = 4
Number of stickers that Bryan has
= 5 u + 11
= 5 x 4 + 11
= 20 + 11
= 31
(b)
Number of stickers that Adam has
= 1 u + 5
= 4 + 5
= 9
(c)
Total number of stickers
= 31 + 9
= 40
(d)
Number of stickers that Bryan has more than Adam
= 31 - 9
= 22
Answer(s): (a) 31; (b) 9; (c) 40; (d) 22