If Adam gives 15 stickers to Bryan, both will have the same number of stickers.
If Bryan gives 9 stickers to Adam, Adam has 7 times as many as Bryan.
- How many stickers does Adam have?
- How many stickers does Bryan have?
- How many stickers do Adam and Bryan have altogether?
- How many stickers does Adam have more than Bryan?
|
Case 1 |
Case 2 |
|
Adam |
Bryan |
Adam |
Bryan |
Before |
4 u + 15 |
4 u - 15 |
7 u - 9 |
1 u + 9 |
Change |
- 15 |
+ 15 |
+ 9 |
- 9 |
After |
4 u |
4 u |
7 u |
1 u |
(a)
Total number of stickers in the end
= 7 u + 1 u
= 8 u
For scenario 1, Adam and Bryan have same number of stickers in the end.
Number of stickers that each boy has in the end
= 8 u ÷ 2
= 4 u
Number of stickers that Bryan has at first in both scenarios is the same.
4 u - 15 = 1 u + 9
4 u - 1 u = 9 + 15
3 u = 24
1 u = 24 ÷ 3 = 8
Number of stickers that Adam has
= 4 u + 15
= 4 x 8 + 15
= 32 + 15
= 47
(b)
Number of stickers that Bryan has
= 1 u + 9
= 8 + 9
= 17
(c)
Total number of stickers
= 47 + 17
= 64
(d)
Number of stickers that Adam has more than Bryan
= 47 - 17
= 30
Answer(s): (a) 47; (b) 17; (c) 64; (d) 30