If Bryan gives 11 stickers to Adam, both will have the same number of stickers.
If Adam gives 17 stickers to Bryan, Bryan has 9 times as many as Adam.
- How many stickers does Bryan have?
- How many stickers does Adam have?
- How many stickers do Bryan and Adam have altogether?
- How many stickers does Bryan have more than Adam?
|
Case 1 |
Case 2 |
|
Bryan |
Adam |
Bryan |
Adam |
Before |
5 u + 11 |
5 u - 11 |
9 u - 17 |
1 u + 17 |
Change |
- 11 |
+ 11 |
+ 17 |
- 17 |
After |
5 u |
5 u |
9 u |
1 u |
(a)
Total number of stickers in the end
= 9 u + 1 u
= 10 u
For scenario 1, Bryan and Adam have same number of stickers in the end.
Number of stickers that each boy has in the end
= 10 u ÷ 2
= 5 u
Number of stickers that Adam has at first in both scenarios is the same.
5 u - 11 = 1 u + 17
5 u - 1 u = 17 + 11
4 u = 28
1 u = 28 ÷ 4 = 7
Number of stickers that Bryan has
= 5 u + 11
= 5 x 7 + 11
= 35 + 11
= 46
(b)
Number of stickers that Adam has
= 1 u + 17
= 7 + 17
= 24
(c)
Total number of stickers
= 46 + 24
= 70
(d)
Number of stickers that Bryan has more than Adam
= 46 - 24
= 22
Answer(s): (a) 46; (b) 24; (c) 70; (d) 22