If Adam gives 7 stickers to Bryan, both will have the same number of stickers.
If Bryan gives 5 stickers to Adam, Adam has 7 times as many as Bryan.
- How many stickers does Adam have?
- How many stickers does Bryan have?
- How many stickers do Adam and Bryan have altogether?
- How many stickers does Adam have more than Bryan?
|
Case 1 |
Case 2 |
|
Adam |
Bryan |
Adam |
Bryan |
Before |
4 u + 7 |
4 u - 7 |
7 u - 5 |
1 u + 5 |
Change |
- 7 |
+ 7 |
+ 5 |
- 5 |
After |
4 u |
4 u |
7 u |
1 u |
(a)
Total number of stickers in the end
= 7 u + 1 u
= 8 u
For scenario 1, Adam and Bryan have same number of stickers in the end.
Number of stickers that each boy has in the end
= 8 u ÷ 2
= 4 u
Number of stickers that Bryan has at first in both scenarios is the same.
4 u - 7 = 1 u + 5
4 u - 1 u = 5 + 7
3 u = 12
1 u = 12 ÷ 3 = 4
Number of stickers that Adam has
= 4 u + 7
= 4 x 4 + 7
= 16 + 7
= 23
(b)
Number of stickers that Bryan has
= 1 u + 5
= 4 + 5
= 9
(c)
Total number of stickers
= 23 + 9
= 32
(d)
Number of stickers that Adam has more than Bryan
= 23 - 9
= 14
Answer(s): (a) 23; (b) 9; (c) 32; (d) 14