Adam has 96 blue stickers.
He has 6 times as many blue stickers as red stickers.
After he buys an equal number of blue and red stickers,
the number of blue stickers is 3 times that of the red stickers.
- How many blue stickers are there in the end?
- How many red stickers are there in the end?
- How many stickers are there in the end?
- How many stickers does Adam buy?
|
Blue stickers |
Red stickers |
Difference |
Before |
6 x 2 = 12 u |
1 x 2 = 2 u |
5 x 2 = 10 u |
Change |
+ ? |
+ ? |
|
After |
3 x 5 = 15 u |
1 x 5 = 5 u |
2 x 5 = 10 u |
(a)
The difference in the number between the blue and red stickers at first and in the end remains unchanged.
LCM of 5 and 2 is 10.
12 u = 96
1 u = 96 ÷ 12 = 8
Number of blue stickers in the end
= 15 u
= 15 x 8
= 120
(b)
Number of red stickers in the end
= 5 u
= 5 x 8
= 40
(c)
Total number of stickers in the end
= 120 + 40
= 160
(d)
Total number of stickers that Adam buys
= (15 u - 12 u) x 2
= 3 u x 2
= 6 u
= 6 x 8
= 48
Answer(s): (a) 120; (b) 40; (c) 160; (d) 48