Adam has 15 blue stickers.
He has 5 times as many blue stickers as red stickers.
After he buys an equal number of blue and red stickers,
the number of blue stickers is 2 times that of the red stickers.
- How many blue stickers are there in the end?
- How many red stickers are there in the end?
- How many stickers are there in the end?
- How many stickers does Adam buy?
|
Blue stickers |
Red stickers |
Difference |
Before |
5 x 1 = 5 u |
1 x 1 = 1 u |
4 x 1 = 4 u |
Change |
+ ? |
+ ? |
|
After |
2 x 4 = 8 u |
1 x 4 = 4 u |
1 x 4 = 4 u |
(a)
The difference in the number between the blue and red stickers at first and in the end remains unchanged.
LCM of 4 and 1 is 4.
5 u = 15
1 u = 15 ÷ 5 = 3
Number of blue stickers in the end
= 8 u
= 8 x 3
= 24
(b)
Number of red stickers in the end
= 4 u
= 4 x 3
= 12
(c)
Total number of stickers in the end
= 24 + 12
= 36
(d)
Total number of stickers that Adam buys
= (8 u - 5 u) x 2
= 3 u x 2
= 6 u
= 6 x 3
= 18
Answer(s): (a) 24; (b) 12; (c) 36; (d) 18