Adam has 60 blue stickers.
He has 4 times as many blue stickers as red stickers.
After he buys an equal number of blue and red stickers,
the number of blue stickers is 2 times that of the red stickers.
- How many blue stickers are there in the end?
- How many red stickers are there in the end?
- How many stickers are there in the end?
- How many stickers does Adam buy?
|
Blue stickers |
Red stickers |
Difference |
Before |
4 x 1 = 4 u |
1 x 1 = 1 u |
3 x 1 = 3 u |
Change |
+ ? |
+ ? |
|
After |
2 x 3 = 6 u |
1 x 3 = 3 u |
1 x 3 = 3 u |
(a)
The difference in the number between the blue and red stickers at first and in the end remains unchanged.
LCM of 3 and 1 is 3.
4 u = 60
1 u = 60 ÷ 4 = 15
Number of blue stickers in the end
= 6 u
= 6 x 15
= 90
(b)
Number of red stickers in the end
= 3 u
= 3 x 15
= 45
(c)
Total number of stickers in the end
= 90 + 45
= 135
(d)
Total number of stickers that Adam buys
= (6 u - 4 u) x 2
= 2 u x 2
= 4 u
= 4 x 15
= 60
Answer(s): (a) 90; (b) 45; (c) 135; (d) 60