Adam has 56 blue stickers.
He has 4 times as many blue stickers as red stickers.
After he buys an equal number of blue and red stickers,
the number of blue stickers is 3 times that of the red stickers.
- How many blue stickers are there in the end?
- How many red stickers are there in the end?
- How many stickers are there in the end?
- How many stickers does Adam buy?
|
Blue stickers |
Red stickers |
Difference |
Before |
4 x 2 = 8 u |
1 x 2 = 2 u |
3 x 2 = 6 u |
Change |
+ ? |
+ ? |
|
After |
3 x 3 = 9 u |
1 x 3 = 3 u |
2 x 3 = 6 u |
(a)
The difference in the number between the blue and red stickers at first and in the end remains unchanged.
LCM of 3 and 2 is 6.
8 u = 56
1 u = 56 ÷ 8 = 7
Number of blue stickers in the end
= 9 u
= 9 x 7
= 63
(b)
Number of red stickers in the end
= 3 u
= 3 x 7
= 21
(c)
Total number of stickers in the end
= 63 + 21
= 84
(d)
Total number of stickers that Adam buys
= (9 u - 8 u) x 2
= 1 u x 2
= 2 u
= 2 x 7
= 14
Answer(s): (a) 63; (b) 21; (c) 84; (d) 14