Adam has 42 red beads.
He has 3 times as many red beads as blue beads.
After he buys an equal number of red and blue beads,
the number of red beads is 2 times that of the blue beads.
- How many red beads are there in the end?
- How many blue beads are there in the end?
- How many beads are there in the end?
- How many beads does Adam buy?
|
Red beads |
Blue beads |
Difference |
Before |
3 x 1 = 3 u |
1 x 1 = 1 u |
2 x 1 = 2 u |
Change |
+ ? |
+ ? |
|
After |
2 x 2 = 4 u |
1 x 2 = 2 u |
1 x 2 = 2 u |
(a)
The difference in the number between the red and blue beads at first and in the end remains unchanged.
LCM of 2 and 1 is 2.
3 u = 42
1 u = 42 ÷ 3 = 14
Number of red beads in the end
= 4 u
= 4 x 14
= 56
(b)
Number of blue beads in the end
= 2 u
= 2 x 14
= 28
(c)
Total number of beads in the end
= 56 + 28
= 84
(d)
Total number of beads that Adam buys
= (4 u - 3 u) x 2
= 1 u x 2
= 2 u
= 2 x 14
= 28
Answer(s): (a) 56; (b) 28; (c) 84; (d) 28