Adam has 40 red stickers.
He has 5 times as many red stickers as blue stickers.
After he buys an equal number of red and blue stickers,
the number of red stickers is 3 times that of the blue stickers.
- How many red stickers are there in the end?
- How many blue stickers are there in the end?
- How many stickers are there in the end?
- How many stickers does Adam buy?
|
Red stickers |
Blue stickers |
Difference |
Before |
5 x 1 = 5 u |
1 x 1 = 1 u |
4 x 1 = 4 u |
Change |
+ ? |
+ ? |
|
After |
3 x 2 = 6 u |
1 x 2 = 2 u |
2 x 2 = 4 u |
(a)
The difference in the number between the red and blue stickers at first and in the end remains unchanged.
LCM of 4 and 2 is 4.
5 u = 40
1 u = 40 ÷ 5 = 8
Number of red stickers in the end
= 6 u
= 6 x 8
= 48
(b)
Number of blue stickers in the end
= 2 u
= 2 x 8
= 16
(c)
Total number of stickers in the end
= 48 + 16
= 64
(d)
Total number of stickers that Adam buys
= (6 u - 5 u) x 2
= 1 u x 2
= 2 u
= 2 x 8
= 16
Answer(s): (a) 48; (b) 16; (c) 64; (d) 16