Adam has 114 blue stickers.
He has 6 times as many blue stickers as red stickers.
After he buys an equal number of blue and red stickers,
the number of blue stickers is 2 times that of the red stickers.
- How many blue stickers are there in the end?
- How many red stickers are there in the end?
- How many stickers are there in the end?
- How many stickers does Adam buy?
|
Blue stickers |
Red stickers |
Difference |
Before |
6 x 1 = 6 u |
1 x 1 = 1 u |
5 x 1 = 5 u |
Change |
+ ? |
+ ? |
|
After |
2 x 5 = 10 u |
1 x 5 = 5 u |
1 x 5 = 5 u |
(a)
The difference in the number between the blue and red stickers at first and in the end remains unchanged.
LCM of 5 and 1 is 5.
6 u = 114
1 u = 114 ÷ 6 = 19
Number of blue stickers in the end
= 10 u
= 10 x 19
= 190
(b)
Number of red stickers in the end
= 5 u
= 5 x 19
= 95
(c)
Total number of stickers in the end
= 190 + 95
= 285
(d)
Total number of stickers that Adam buys
= (10 u - 6 u) x 2
= 4 u x 2
= 8 u
= 8 x 19
= 152
Answer(s): (a) 190; (b) 95; (c) 285; (d) 152