Adam has 60 red stickers.
He has 6 times as many red stickers as blue stickers.
After he buys an equal number of red and blue stickers,
the number of red stickers is 3 times that of the blue stickers.
- How many red stickers are there in the end?
- How many blue stickers are there in the end?
- How many stickers are there in the end?
- How many stickers does Adam buy?
|
Red stickers |
Blue stickers |
Difference |
Before |
6 x 2 = 12 u |
1 x 2 = 2 u |
5 x 2 = 10 u |
Change |
+ ? |
+ ? |
|
After |
3 x 5 = 15 u |
1 x 5 = 5 u |
2 x 5 = 10 u |
(a)
The difference in the number between the red and blue stickers at first and in the end remains unchanged.
LCM of 5 and 2 is 10.
12 u = 60
1 u = 60 ÷ 12 = 5
Number of red stickers in the end
= 15 u
= 15 x 5
= 75
(b)
Number of blue stickers in the end
= 5 u
= 5 x 5
= 25
(c)
Total number of stickers in the end
= 75 + 25
= 100
(d)
Total number of stickers that Adam buys
= (15 u - 12 u) x 2
= 3 u x 2
= 6 u
= 6 x 5
= 30
Answer(s): (a) 75; (b) 25; (c) 100; (d) 30