Adam has 54 red stickers.
He has 6 times as many red stickers as blue stickers.
After he buys an equal number of red and blue stickers,
the number of red stickers is 2 times that of the blue stickers.
- How many red stickers are there in the end?
- How many blue stickers are there in the end?
- How many stickers are there in the end?
- How many stickers does Adam buy?
|
Red stickers |
Blue stickers |
Difference |
Before |
6 x 1 = 6 u |
1 x 1 = 1 u |
5 x 1 = 5 u |
Change |
+ ? |
+ ? |
|
After |
2 x 5 = 10 u |
1 x 5 = 5 u |
1 x 5 = 5 u |
(a)
The difference in the number between the red and blue stickers at first and in the end remains unchanged.
LCM of 5 and 1 is 5.
6 u = 54
1 u = 54 ÷ 6 = 9
Number of red stickers in the end
= 10 u
= 10 x 9
= 90
(b)
Number of blue stickers in the end
= 5 u
= 5 x 9
= 45
(c)
Total number of stickers in the end
= 90 + 45
= 135
(d)
Total number of stickers that Adam buys
= (10 u - 6 u) x 2
= 4 u x 2
= 8 u
= 8 x 9
= 72
Answer(s): (a) 90; (b) 45; (c) 135; (d) 72