Adam has 50 red stickers.
He has 5 times as many red stickers as blue stickers.
After he buys an equal number of red and blue stickers,
the number of red stickers is 2 times that of the blue stickers.
- How many red stickers are there in the end?
- How many blue stickers are there in the end?
- How many stickers are there in the end?
- How many stickers does Adam buy?
|
Red stickers |
Blue stickers |
Difference |
Before |
5 x 1 = 5 u |
1 x 1 = 1 u |
4 x 1 = 4 u |
Change |
+ ? |
+ ? |
|
After |
2 x 4 = 8 u |
1 x 4 = 4 u |
1 x 4 = 4 u |
(a)
The difference in the number between the red and blue stickers at first and in the end remains unchanged.
LCM of 4 and 1 is 4.
5 u = 50
1 u = 50 ÷ 5 = 10
Number of red stickers in the end
= 8 u
= 8 x 10
= 80
(b)
Number of blue stickers in the end
= 4 u
= 4 x 10
= 40
(c)
Total number of stickers in the end
= 80 + 40
= 120
(d)
Total number of stickers that Adam buys
= (8 u - 5 u) x 2
= 3 u x 2
= 6 u
= 6 x 10
= 60
Answer(s): (a) 80; (b) 40; (c) 120; (d) 60