Adam has 24 red beads.
He has 6 times as many red beads as blue beads.
After he buys an equal number of red and blue beads,
the number of red beads is 3 times that of the blue beads.
- How many red beads are there in the end?
- How many blue beads are there in the end?
- How many beads are there in the end?
- How many beads does Adam buy?
|
Red beads |
Blue beads |
Difference |
Before |
6 x 2 = 12 u |
1 x 2 = 2 u |
5 x 2 = 10 u |
Change |
+ ? |
+ ? |
|
After |
3 x 5 = 15 u |
1 x 5 = 5 u |
2 x 5 = 10 u |
(a)
The difference in the number between the red and blue beads at first and in the end remains unchanged.
LCM of 5 and 2 is 10.
12 u = 24
1 u = 24 ÷ 12 = 2
Number of red beads in the end
= 15 u
= 15 x 2
= 30
(b)
Number of blue beads in the end
= 5 u
= 5 x 2
= 10
(c)
Total number of beads in the end
= 30 + 10
= 40
(d)
Total number of beads that Adam buys
= (15 u - 12 u) x 2
= 3 u x 2
= 6 u
= 6 x 2
= 12
Answer(s): (a) 30; (b) 10; (c) 40; (d) 12