Adam has 45 blue stickers.
He has 5 times as many blue stickers as red stickers.
After he buys an equal number of blue and red stickers,
the number of blue stickers is 3 times that of the red stickers.
- How many blue stickers are there in the end?
- How many red stickers are there in the end?
- How many stickers are there in the end?
- How many stickers does Adam buy?
|
Blue stickers |
Red stickers |
Difference |
Before |
5 x 1 = 5 u |
1 x 1 = 1 u |
4 x 1 = 4 u |
Change |
+ ? |
+ ? |
|
After |
3 x 2 = 6 u |
1 x 2 = 2 u |
2 x 2 = 4 u |
(a)
The difference in the number between the blue and red stickers at first and in the end remains unchanged.
LCM of 4 and 2 is 4.
5 u = 45
1 u = 45 ÷ 5 = 9
Number of blue stickers in the end
= 6 u
= 6 x 9
= 54
(b)
Number of red stickers in the end
= 2 u
= 2 x 9
= 18
(c)
Total number of stickers in the end
= 54 + 18
= 72
(d)
Total number of stickers that Adam buys
= (6 u - 5 u) x 2
= 1 u x 2
= 2 u
= 2 x 9
= 18
Answer(s): (a) 54; (b) 18; (c) 72; (d) 18