Adam has 100 blue beads.
He has 4 times as many blue beads than red beads.
After he gives away an equal number of blue and red beads,
the number of blue beads is 6 times that of the red beads.
- How many blue beads are there in the end?
- How many red beads are there in the end?
- How many beads are there in the end?
- How many beads does Adam give away?
|
Blue beads |
Red beads |
Difference |
Before |
4 x 5 = 20 u |
1 x 5 = 5 u |
3 x 5 = 15 u |
Change |
- ? |
- ? |
|
After |
6 x 3 = 18 u |
1 x 3 = 3 u |
5 x 3 = 15 u |
(a)
The difference in the number between the blue and red beads at first and in the end remains unchanged.
LCM of 3 and 5 is 15.
20 u = 100
1 u = 100 ÷ 20 = 5
Number of blue beads in the end
= 18 u
= 18 x 5
= 90
(b)
Number of red beads in the end
= 3 u
= 3 x 5
= 15
(c)
Total number of beads in the end
= 90 + 15
= 105
(d)
Total number of beads that Adam gives away
= (20 u - 18 u) x 2
= 2 u x 2
= 4 u
= 4 x 5
= 20
Answer(s): (a) 90; (b) 15; (c) 105; (d) 20