Adam has 66 red beads.
He has 2 times as many red beads than blue beads.
After he gives away an equal number of red and blue beads,
the number of red beads is 4 times that of the blue beads.
- How many red beads are there in the end?
- How many blue beads are there in the end?
- How many beads are there in the end?
- How many beads does Adam give away?
|
Red beads |
Blue beads |
Difference |
Before |
2 x 3 = 6 u |
1 x 3 = 3 u |
1 x 3 = 3 u |
Change |
- ? |
- ? |
|
After |
4 x 1 = 4 u |
1 x 1 = 1 u |
3 x 1 = 3 u |
(a)
The difference in the number between the red and blue beads at first and in the end remains unchanged.
LCM of 1 and 3 is 3.
6 u = 66
1 u = 66 ÷ 6 = 11
Number of red beads in the end
= 4 u
= 4 x 11
= 44
(b)
Number of blue beads in the end
= 1 u
= 1 x 11
= 11
(c)
Total number of beads in the end
= 44 + 11
= 55
(d)
Total number of beads that Adam gives away
= (6 u - 4 u) x 2
= 2 u x 2
= 4 u
= 4 x 11
= 44
Answer(s): (a) 44; (b) 11; (c) 55; (d) 44