Adam has 280 red beads.
He has 4 times as many red beads than blue beads.
After he gives away an equal number of red and blue beads,
the number of red beads is 6 times that of the blue beads.
- How many red beads are there in the end?
- How many blue beads are there in the end?
- How many beads are there in the end?
- How many beads does Adam give away?
|
Red beads |
Blue beads |
Difference |
Before |
4 x 5 = 20 u |
1 x 5 = 5 u |
3 x 5 = 15 u |
Change |
- ? |
- ? |
|
After |
6 x 3 = 18 u |
1 x 3 = 3 u |
5 x 3 = 15 u |
(a)
The difference in the number between the red and blue beads at first and in the end remains unchanged.
LCM of 3 and 5 is 15.
20 u = 280
1 u = 280 ÷ 20 = 14
Number of red beads in the end
= 18 u
= 18 x 14
= 252
(b)
Number of blue beads in the end
= 3 u
= 3 x 14
= 42
(c)
Total number of beads in the end
= 252 + 42
= 294
(d)
Total number of beads that Adam gives away
= (20 u - 18 u) x 2
= 2 u x 2
= 4 u
= 4 x 14
= 56
Answer(s): (a) 252; (b) 42; (c) 294; (d) 56